Find the atomic structure of `._(20)^(40)Ca`.

Find the atomic structure of ._(12)^(24)Mg . What is its valency?

Atomic structure: Lecture 20

Atomic structure: Lecture 20

What is the minimum photon energy required to remove the least bound neutron of ._(20)^(40)Ca and ._(18)^(40)Ar . The nesessary atomic masses (in mu ) are given below: {:(M(.^(40)Ca)=39.962591 u),(M(.^(39)Ca)=38.970719 u),(M(.^(40)Ar)=39.962383 ),(M(.^(39)Ar)=38.964314 u),(" "m_n=1.008665 u):}

An isobar of ""_(20)^(40)Ca is

An isobar of ._(20)Ca^(40) is

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

In a radioactive sample. ._(19)^(40)K nuclei either decay into stable ._(20)^(40)Ca nuclei with decay constant 4.5 xx 10^(-10) per year or into stable ._(18)^(40)Ar nuclei with decay constant 0.5 xx 10^(-10) per year. Given that in this sample all the stable ._(20)^(40)Ca and ._(18)^(40)Ar nuclei are produced by the ._(19)^(40)K nuclei only. In time t xx 10^9 years. If the ratio of the sum of stable ._(20)^(40)Ca and ._(18)^(40)Ar nuclei to the radioactive ._(19)^(40)K nuclei is 99. The value of t will be. [Given : In 10 = 2.3]