Complete the nuclear reaction and calculate the energy released.
`._(3)^(7)Li + |H ("proton") rarr ._(2)^(4) He + ? + Q`
`{:("Given that mass of lithium atom ",=,7.01822,am u,),("Mass of proton",=,1.00812,am u,),("Mass of " alpha-"particle",=,4.00390,am u,):}`

Calculate the binding energy of helium nucleus (._(2)^(4)He) and express the quantity in MeV and J {:("Mass of helium nucleus",=,4.0028,am u,),("Mass of proton",=,1.00758,am u,),("Mass of neutron",=,1.00897,am u,):}

Calculate the binding energy of the lithium atom (._(3)^(7)Li) from the following data: {:("mass of proton",= 1.00759,am u,),("mass of neutron",= 1.00898,am u,),("mass of electron",= 0.00055,am u,),("mass of lithium atom",= 7.01818,am u,):}

Calculate the energy released in kilowatt-hours when 100g of ._(3)^(7)Li are converted into ._(2)^(4)He by proton bombardment. Mass of ._(3)^(7)Li = 7.0183 am u , mass of proton = 1.0081 amu. Write down the nuclear reaction.

Calculate the binding energy of an alpha -particles. Given that mass of proton =1.0073u , mass of neutron =1.0087 u . And mass of alpha -particle =4.0015 u .

Calculate the energy generated in kWh, when 100g of ._(3)Li(7) . are converted into ._(2)He(4) by proton bombardment. Given mass of ._(3)Li(7)=7.0183a.m.u , mass of ._(2)He(4)=4.0040a.m.u , mass of ._(1)H(1)atom=1.0081a.m.u.

A neutron is absorbed by a ._(3)^(6)Li nucleus with the subsequent emission of an alpha particle. (i) Write the corresponding nuclear reaction. (ii) Calculate the energy released, in MeV , in this reaction. [Given: mass ._(3)^(6)Li=6.015126u , mass (neutron) =1.0086654 u mass (alpha particle) =0.0026044 u and mass (triton) =3.010000 u . Take i u=931 MeV//c^(2) ]

calculate the energy released in the nuclear fusion of isotopes of hydrogen (i) ._(1)^(2)H + ._(1)^(2)H rarr ._(2)^(3)He + ._(0)^(1)n (ii) ._(1)^(2)H + ._(1)^(3)H rarr ._(2)^(4)He + ._(0)^(1)n Given that mass of neutron = 1.00867 amu {:("mass of",._(1)^(2)H = 2.01410,am u,),("mas of",._(1)^(3)H = 3.01603,am u,),("mass of ",._(2)^(3)H = 3.0160,am u,),("mass of ",._(2)^(4)He = 4.00260,am u,):}

Calculate the binding energy per nucleon of ._26Fe^(56) nucleus. Given that mass of ._26Fe^(56)=55.934939u , mass of proton =1.007825u and mass of neutron =1.008665 u and 1u=931MeV .

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .