Calculate how much coal is equivalent to 1kg of `.^(235)U`. Given that 200 MeV is released per fission process and 8000 kcal is released as heat of combustion of 1 kg of coal. Avogadro constant `= 6.1 xx 10^(26) Kg mol^(-1)`

Calculate the energy released by fission of 1 g of ._(92)^(235)U , assuming that an energy of 200 MeV is released by fission of each atom of .^(235)U . (Avogardo constant is = 6.023 xx 10^(26) kg mol^(-1) )

Calculate the energy released by fission from 2 g of .^(235)._(92)U in kWh . Given that the energy released per fission is 200 MeV .

The amount of energy released in burning 1 kg of coal is

The energy in MeV is released due to transformation of 1 kg mass completely into energy (c = 3 xx 10^8 m//s) .

Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))

Calculate the amount of ""_(92)U^(235) required to release energy of 1 kWh. Given energy released during fission of one atom is 200 MeV.

A reaction develop nuclear energy at the rate of 3 xx 10^(4) kW . How many atoms of .^(215)U undergo fission per second? How much .^(235)U is burnt in 1000 hours of operation ? (Assume that 200 Mev is released per fission and Avogadro constant is 6.023 xx 10^(26) per kg mole)

The energy liberated on complete fission of 1 kg of ._92 U^235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus).