Calculate the energy released in kilowat...

Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `._(2)^(4)He` by proton bombardment. Mass of `._(3)^(7)Li = 7.0183 am u`, mass of proton = 1.0081 amu. Write down the nuclear reaction.

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The correct Answer is:

`._(3)^(7)Li + ._(1)^(1)H` (proton) `rarr 2 ._(2)^(4)He + Q` (energy released), 6.554 xx 10^(6) kWh`

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Calculate the energy generated in kWh, when 100g of ._(3)Li(7) . are converted into ._(2)He(4) by proton bombardment. Given mass of ._(3)Li(7)=7.0183a.m.u , mass of ._(2)He(4)=4.0040a.m.u , mass of ._(1)H(1)atom=1.0081a.m.u.

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