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Stationery nucleus .^(238)U decays by a ...

Stationery nucleus `.^(238)U` decays by a emission generaring a total kinetic energy T:
`._(92)^(238) rarr ._(90)^(234)Th +._2^4 alpha`
What is the kinetic energy of the `alpha`-particle?

Text Solution

Verified by Experts

The correct Answer is:
`8.8 xx 10^(-13)J`
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