[" 2.Fraffica "],[[" (i) "[[a,b],[-b,a]]+[[a,b],[b,a]]]]

If A=[[a+i b, c+i d],[-c+i d, a-i b]] and a^2+b^2+c^2+d^2=1,t h e n ,A^(-1) is equal to a. [[a+i b,-c+i d],[c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]] and a^2+b^2+c^2+d^2=1,t h e n ,A^(-1) is equal to a. [[a+i b,-c+i d],[c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]]a n da^2+b^2+c^2+d^2=1,t h e nA^(-1) is equal to a.[[a+i b,-c+i d],[-c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]]a n da^2+b^2+c^2+d^2=1,t h e nA^(-1) is equal to a. [[a+i b,-c+i d],[-c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If A=[[i,-i],[-i ,i]] and B=[[1,-1],[-1 ,1]], t hen ,A^8 equals a. 4B b. 128 B c. -128 B d. -64 B

If A=[[i,-i],[-i ,i]] and B=[[1,-1],[-1 ,1]], t hen ,A^8 equals a. 4B b. 128 B c. -128 B d. -64 B

If A=[[i,2i],[-3,2]] and B=[[2i,i],[2,-3]] ,where sqrt-1=(i) find A+B and A-B .Show that A+B is a singular.A-B a singular? Justify your answer.

If A=[[i,-i],[-i, i ]] and B=[[1,-1],[-1,1]] ,then A^( 8 ) equals,(where i=sqrt(-1) ) 4B 128 B -128 B -64 B

If A=[[i,0],[0,i]] and B=[[0,-i],[-1,0]] then (A+B)(A-B)=

In the binary operation **: QxxQrarrQ is defined as : (i) a**b=a+b-ab, a,b inQ