(tes)^(-1/3)

Calculate te radus of an isolated sphere of density 3.0 g cm^(-3) from the surface of which the escape velocity be 40 ms^(-1)

Calculate te radus of an isolated sphere of density 3.0 g cm^(-3) from the surface of which the escape velocity be 40 ms^(-1)

Let g (x ) = x ^(C )e ^(Cx) and f (x) = int _(0)^(x) te ^(2r) (1+3t ^(2))^(1//2) dt. If L = lim _(x to oo) (f'(x ))/(g '(x)) is non-zero finite number then : The valur of C is:

Let g (x ) = x ^(C )e ^(Cx) and f (x) = int _(0)^(x) te ^(2t) (1+3t ^(2))^(1//2) dt. If L = lim _(x to oo) (f'(x ))/(g '(x)) is non-zero finite number then : The value of L . Is :

Let g (x ) = x ^(C )e ^(Cx) and f (x) = int _(0)^(x) te ^(2t) (1+3t ^(2))^(1//2) dt. If L = lim _(x to oo) (f'(x ))/(g '(x)) is non-zero finite number then : The value of L . Is :

Let g (x ) = x ^(C )e ^(Cx) and f (x) = int _(0)^(x) te ^(2r) (1+3t ^(2))^(1//2) dt. If L = lim _(x to oo) (f'(x ))/(g '(x)) is non-zero finite number then : The valur of C is:

The instantaneous rate of change at t=1 for the function f(t)=te^(-1)+9 is

Iff(y)=e^(y),g(y)>0, and F(t)=int_(0)^(t)t(t-y)dt, then F(t)=e^(t)-(1+t)F(t)=te^(t)F(t)=te^(-1)(d)F(t)=1-e^(t)(1+t)

g(x),=x^(c)e^(cx) and f(x)=int_(0)^(x)te^(2t)(1+3t^(2))^((1)/(2))dt* if L,=lim_(x rarr oo)(f'(x))/(g'(x)) is non-zero finit number then :,

If (1)/(x)=(1)/(y)=(1)/(z)+(1)/(w) , then make w as te subject of the formula.