You are provided with 3 capacitors, each capacitance `2muF`. In how many possible ways can you connect these capacitors. Calculate the capacitance of each of the combinations.

Explanation

(i)
`C_(s)=(C)/(n)=(C)/(3)`
i.e., `C_(s)=(2)/(3)muF`
(ii)
`C_(P)=nC,C_(p)=3xx2muF=6muF`
(iii)
`C_(AB)=(C)/(2)+C=((3)/(2))C=(3)/(2)xx2muF`
or `C_(AB)=3muF`
(iv)
`C_(AB)=((2C)C)/(3C)=(2)/(3)C`
i.e., `C_(AB)=(2)/(3)xx2muF=(4)/(3)muF`