[qquad [c(x)(bx)/(a)+(ay)/(b)=a^(2)+b^(2)],[x+y=2ab]],[" ANSWERS "]

(bx)/(a)-(ay)/(b)+a+b=0 and bx-ay+2ab

If (x+1)/(x-1)=(a)/(b) and (1-y)/(1+y)=(b)/(a), then the value of (x-y)/(1+xy) is (2ab)/(a^(2)-b^(2)) (b) (a^(2)-b^(2))/(2ab) (c) (a^(2)+b^(2))/(2ab) (d) (a^(2)-b^(2)backslash)/(ab)

Solve the following system of equations in x and yax+by=1bx+ay=((a+b)^(2))/(a^(2)+b^(2))-1 or,bx+ay=(2ab)/(a^(2)+b^(2))

Solve (by any method) : (x+a)/(2a+b)=(y+2b)/(a+b) bx+ay=a^(2)+b^(2)

If bx^(2)+ay^(2)=(x+y)^(2)," then " (dy)/(dx)=

Factorise the following expressions : (i) ax-ay+bx-by " " (ii) x^(2)-x-ax+a " " (iii) x^(4)+x^(3)+x^(2)+x (iv) 16(a+b)^(2)-4a-4b " " (v) x^(2)+(1)/(x^(2))+2-3x-(3)/(x) " " (vi) x^(2)-((a)/(b)+(b)/(a))x+1 (vii) x^(2)+(a-(1)/(a))x-1 " " (viii)ab(x^(2)+y^(2)+xy(a^(2)+b^(2)) " "(ix) (ax+by)^(2)+(bx-ay)^(2)

If ax+by=1 and bx+ay=(2ab)/(a^(2)+b^(2)) then (x^(2)+y^(2))(a^(2)+b^(2)) is equal to

Find the value of y by eliminating x : (x+a)/(2a+b)=(y+2b)/(a+b), bx+ay=a^(2)+b^(2)