The equation of the plane through the point (-1,2, 0) and parallel to the lines `x/3=(y+1)/0=(z-2)/-1 and (x-1)/1=(y+1)/2=(2z+5)/-1` is

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0

The equation of the plane through the point (1,2,3) and parallel to the plane x+2y+5z=0 is

The equation of the plane through the point (1,2,3) and parallel to the plane x+2y+5z=0 is

The equation of the plane through the point (-1,2,0) and parallel to the line (x)/(3)=(y+1)/(0)=(z-2)/(-1) and (x)/(3)=(2y+1)/(2)=(2z+1)/(-1) is

The equation of the plane through the point (2,-1,-3) and parallel to the lines (x-1)/(3)=(y+2)/(2)=(z)/(-4) and (x)/(2)=(y-1)/(-3)=(z-2)/(2) is

The equation of the plane through the point (2,-1,-3) and parallel to the lines (x-1)/(3)= (y+2)/(2)= ( z)/(-4) and ( x)/(2)= (y-1)/(-3) = (z-2)/(2) is

Find the Cartesian and vector equation of the plane passing through the point (2,0,-1) and parallel to to the lines. x/-3=(y-2)/4=z+1 and x-4=(1-y)/2=2z .