Differentiate the following function `3e^(-3x)"log"(1+x)`

Explanation

To differentiate the function \( y = 3e^{-3x} \log(1+x) \), we will use the product rule of differentiation. The product rule states that if we have two functions \( u \) and \( v \), then the derivative of their product is given by:

\[ \frac{dy}{dx} = u'v + uv' \]

### Step 1: Identify the functions
Let:
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