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[cos40+cos80+cos160+cos17" point "],[240...

[cos40+cos80+cos160+cos17" point "],[240=],[00],[01],[01/2]

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cos40 + cos80 + cos160 + cos240

cos20^@cos40^@cos80^@=

cos40^(@)+cos 80^(@)+cos160^(@)+cos240^(@) =

cos 40^(@) + cos 80^(@) + cos 160^(@) =

cos 40^0+cos 80^0+cos 160^0+cos 240^0= a. 0 b. 1 c. 1//2 d. -1//2

cos 40^0+cos 80^0+cos 160^0+cos 240^0= 0 b. 1 c. 1//2 d. -1//2

Show that cos20^o cos40^o cos60^o cos80^o =1/16

cos20 ^ (@) cos40 ^ (@) cos80 ^ (@) =

cos 20^(@) cos 40^(@) cos 80^(@)=

Cos 40^(@) + Cos80^(@) + Cos160^(@) + Cos240^(@) =