3x+2y=4

Area of triangle formed by straight lines 3x - y = 3, x - 2y + 4 =0 and y =0 is

x^(2)-3x^(2)y-4x+7 if x=-2,y=2

If the ordered pairs (x^(2) - 3x, y^(2) + 4y ) and (-2,5) are equal , then find x and y .

If the ordered pairs (x^(2)-3x, y^(2)+4y) and (-2, 5) are equal to then find x and y.

Draw the graphs of equations : 3x - y = 3 x - 2y = - 4. Shade the area of region bounded by the lines and x-axis.

2. 5 The solution of (dy)/(dx)=(2x-y+3)/(x+2y+4) is

Subtract: 3/2x-5/4y-7/2z\ from2/3x+3/2y-4/3z