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Differentiate sin^(-1){(2^(x+1). 3^x)...

Differentiate `sin^(-1){(2^(x+1). 3^x)/(1+(36)^x)}"with respect to"xdot`

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To differentiate the function \( y = \sin^{-1}\left(\frac{2^{x+1} \cdot 3^x}{1 + (36)^x}\right) \) with respect to \( x \), we will follow these steps: ### Step 1: Rewrite the expression First, we can simplify the expression inside the inverse sine function: \[ y = \sin^{-1}\left(\frac{2 \cdot 2^x \cdot 3^x}{1 + (6^2)^x}\right) = \sin^{-1}\left(\frac{2 \cdot 2^x \cdot 3^x}{1 + 6^{2x}}\right) \] This can be rewritten as: ...
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  3. Differentiate sin^(-1){(2^(x+1). 3^x)/(1+(36)^x)}"with respect to"x...

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  14. Differentiate sin^(-1)((2x)/(1+x^2)) with respect to tan^(-1)((2...

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