If the equation `3x^2 + 3y^2 + 6lambdax + 2lambda = 0` represents a circle, then the value of `lambda`. lies in

2x^2 +2y^2 +4 lambda x+lambda =0 represents a circle for

2x^(2)+2y^(2)+4 lambda x+lambda=0 represents a circle for

If the equation x^(2)+y^(2)+6x-2y+(lambda^(2)+3lambda+12)=0 represent a circle. Then

If the equation x^(2)+y^(2)+6x-2y+(lambda^(2)+3lambda+12)=0 represent a circle. Then

If the equation lambdax^2+ 4xy + y^2 + lambdax + 3y + 2 = 0 represent a parabola then find lambda .

If the equation lambda x^2+(2 lambda-3)y^2-4x-1=0 represents a circle, then its radius is :

2x^(2)+2y^(2)+2 lambda x+lambda^(2)=0 represents a circle for

If the equation x^(2)+y^(2)+2 lambda x+4=0 and x^(2)+y^(2)-4 lambda y+8=0 represent real circles then the valueof lambda can be

If the equation (4 lambda - 3) x^(2) + lambda y ^(2) + 6x - 2y + 2 = 0 represents a circle, then its centre is