If `x=(t+1/t)^a ,y=a^(t+1/t),"f i n d"(dy)/(dx)`

Explanation

To find \(\frac{dy}{dx}\) where \(x = \left(t + \frac{1}{t}\right)^a\) and \(y = a^{\left(t + \frac{1}{t}\right)}\), we will use the chain rule.

### Step-by-Step Solution:

1. **Differentiate \(y\) with respect to \(t\)**:
\[ y = a^{\left(t + \frac{1}{t}\right)} \]
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