If `x=a((1+t^2)/(1-t^2))"and"y=(2t)/(1-t^2),"f i n d"(dy)/(dx)`

Explanation

To find \(\frac{dy}{dx}\) given the equations \(x = a\left(\frac{1+t^2}{1-t^2}\right)\) and \(y = \frac{2t}{1-t^2}\), we will use the chain rule since both \(x\) and \(y\) are functions of \(t\).

### Step-by-Step Solution:

1. **Differentiate \(y\) with respect to \(t\)**:
\[ y = \frac{2t}{1-t^2} \]
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