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Find the point on the curve y=x^3-11 x+5...

Find the point on the curve `y=x^3-11 x+5`at which the tangent is `y = x - 11`.

Text Solution

Verified by Experts

Equation of the tangent is ,
`y = x -11`
Comparing it with `y = mx+c`,
`m = 1`
So, slope of the tangent is `1`.
Now, equation of the curve is,
`y = x^3-11x+5`
`:. 1 = dy/dx = 3x^2-11`
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