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Let +6 (addition modulo 6) be a binar...

Let `+_6` (addition modulo 6) be a binary operation on `S={0,\ 1,\ 2,\ 3,\ 4,\ 5}` . Write the value of `2+_6 4^(-1)+_6 3^(-1)` .

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These two intersect at 0 .
` Rightarrow a+{ }_{6} 0=0+_{6} a=a, forall a in S`
So, 0 is the identity element.
From the table,
`4+62=0 `
` ...
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