sin[cot^(-1)[cos(tan^(-2)n)]

sin{cot^(-1)[cos(tan^(-1)x)]}=....

sin[cot^(-1){cos(tan^(-1)x)}]=

If A=sin[cot^(-1){cos(tan^(-1)x)}], then

Prove that: "sin"[cot^(-1){"cos"(tan^(-1)x)}]=sqrt((x^2+1)/(x^2+2)) cos [tan^(-1) (cot^(-1)x)}]=sqrt((x^2+1)/(x^2+2))

Find the value of sin cot^-1 cos (tan^-1(2))

sin(Cot^(-1)(cos(Tan^(-1)x)))=

sin cot ^ (- 1) cos tan ^ (- 1) 2 =

sin cot ^ (- 1) cos tan ^ (- 1) 2

sin {cot^(-1)[tan (cos^(-1)x)]=