[7x+4y=10],[-35x+12y=25]

The incentre of the triangle formed by the lines 3x + 4y =10,5x+12y = 26, 7x+24y-50 is (alpha,beta) then alpha+beta= (i)0 (ii)1 (iii)2 (iv)4

Solve the following pair of linear equations by cross multiplication method : 4x+7y=10 , 10x- 35/2 y = 25 .

A point equidistant from the lines 4x+3y+10=0, 5x-12y+26=0 and 7x+24y-50=0 is :

A point equidistant from the lines 4x+3y+10=0, 5x-12y+26=0 and 7x+24y-50=0 is:

Show that the origin is equidistant from the three straight lines : 4x + 3y + 10 = 0,5x - 12y + 26 =0 and 7x + 24y = 50.

A point equidistant from the line 4x+3y+10=0,5x-12y+26=0 and 7x+24y-50=0 is

Find three different solutions of the each of the following equations. (i) 3x + 4y = 7 (ii) y = 6x (iii) 2x - y = 7 (iv) 13x - 12y = 25 (v) 10x + 11y = 21 (vi) x + y = 0

Find three different solutions of the each of the following equations. (i) 3x + 4y = 7 (ii) y = 6x (iii) 2x - y = 7 (iv) 13x - 12y = 25 (v) 10x + 11y = 21 (vi) x + y = 0