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A hanging block of mass m' prevents the ...

A hanging block of mass m' prevents the smaller block of mass m from slipping over a movable triangular block of mass M. All the surface are frictionless and the strings and the pulleys are light. Value of mass m' in terms of m, M and `theta` is

A

`[(m+M)/(cot theta - 1)]`

B

`[(m-M)/(cot theta + 1)]`

C

`[(m-M)/(cot theta - 2)]`

D

`[(m+M)/(cot theta - 2)]`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The block of mass m is at rest. Find the tension in the string A .

    A
    mg
    B
    2 mg
    C
    3 mg
    D
    4 mg

  • Find the acceleration of the block of mass m. Assume pulleys are massless and frictionless.

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    D
    None

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    B
    `(M)/(M + m) g`
    C
    `(M + m)/(mn) g`
    D
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