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int(ln((x-1)/(x+1)))/(x^2-1)dx is equal ...

`int(ln((x-1)/(x+1)))/(x^2-1)dx` is equal to

A

`1/2(ln((x-1)/(x+1)))^(2) + C`

B

`1/2(ln((x+1)/(x-1)))^(2) + C`

C

`1/4(ln((x-1)/(x+1)))^(2) + C`

D

`1/4(ln((x+1)/(x-1)))^(2) + C`

Text Solution

Verified by Experts

The correct Answer is:
C
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