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The figure below shows a battery of emf ...

The figure below shows a battery of emf `epsilon` connected to an inductor L and resistance R in series. If the switch is closed at t=0, then the total charge that flows from the battery in time constant of the circuit is

A

`( epsilon L)/( R^(2)) ( 1- ( 1)/(e ) )`

B

`( epsilonL)/( 2 e R^(2))`

C

`( epsilon L)/( 4 e R^(2))`

D

`( epsilon L)/( e R^(2))`

Text Solution

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The correct Answer is:
D
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