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The solubility product of AgCl is 1.8xx1...

The solubility product of AgCl is `1.8xx10^(-10)`. Precipitation of AgCl will occur only when equal volumes of solutions of :

A

`10^(-4)M" "Ag^(+) and 10^(-4)M" "Cl^(-)`

B

`10^(-7)M" "Ag^(+) and 10^(-7)"M "Cl^(-)`

C

`10^(-5)M" "Ag^(+) and 10^(-5)M" "Cl^(-)`

D

`10^(-10)" M "Ag^(+) and 10^(-10)" M "Cl^(-)`

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The correct Answer is:
A
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