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In an excited state of hydrogen like ato...

In an excited state of hydrogen like atom an electron has total energy of `-3.4 eV`. If the kinetic energy of the electron is E and its de-Broglie wavelength is `lambda`, then

A

`E=6.eV, lambda~6.6xx10^(-10)m`

B

`E=3.4 eV, lambda~6.6xx10^(-10)m`

C

`E=3.4eV, lambda~6.6xx10^(-11)m`

D

`E=6.8eV, lambda~6.6 xx10^(-11)m`

Text Solution

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The correct Answer is:
B
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