Let `A=R-[2]a n dB=R-[1]dot` If `f: AvecB` is a mapping defined by `f(x)=(x-1)/(x-2)` , show that `f` is bijective.

Explanation

We have,

`A=R-{2} and B=R-{1}`.If A`->`B is mapping defined.
`

f(x)=frac{x-1}{x-2}`


Let` x, y in A` such that
`

f(x)=f(y)`

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