Given examples of two one-one functions `f_1a n df_2` from `R` to `R` such that `f_1+f_2: RvecR ,` defined by `(f_1+f_2)(x)=f_1(x)+f_2(x)` is not one-one.

Explanation

We know that `f_{1}: R -> R,` given by `f_{1}(x)=x_{r} and f_{2}(x)=-x `are one-one. Proving `f_{1}` is one-one:

`Let f_{1}(x)=f_{1}(y)`


`Rightarrow {x}={y}`


So,` f_{1} `is one-one.

Proving `f_{2} `is one-one:
Let` f_{2}(x)=f_{2}(y)`

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