sin^(2)-4m-2=0

Find the number of solutions of the equation sin^(4)x+cos^(4)x-2sin^(2)x+(3)/(4)sin^(2)2x=0 in the interval [0,2 pi]

if m belongs to [-1,0], then prove that the equation sin^(4)x+(m+1)sin^(2)x+m=0 is satisfied by all real values of x.

Solve using formula 5m^2 - 4m -2 = 0

If D_(r)=|{:(2r-1,""^(m)C_(r),1),(m^(2)-1,2^(m),m+1),(sin^(2)(m^(2)),sin^(2)(m),sin^(2)(m+1)):}| then find sum_(r=0)^(m)D_(r) .

If Delta_( r)= |(2r-1, ""^(m)C_(r ), 1),(m^(2)-1, 2^(m), m+1), ("sin"^(2)(m^(2)), "sin"^(2)(m), "sin"^(2)(m+1))| then sum_(r =0)^(m)Delta_(r )=

Solve the equation sin^4x+cos^4x-2sin^2x+(3sin^2 2x)/4=0

Solve the equation sin^4x+cos^4x-2sin^2x+(3sin^2 2x)/4=0

Solve the equation sin^4x+cos^4x-2sin^2x+(3sin^2 2x)/4=0

If the equation x^(2)-(2+m)x+(m^(2)-4m+4)=0 in x has equal roots, then the values of m are