" a) "y=x^(3)-4x pi1

The area of the region described by A={(x,y):x^(2)+y^(2)<=1 and quad y^(2)<=1-x} is (1) (pi)/(2)+(4)/(3)(2)(pi)/(2)-(4)/(3)(3)(pi)/(2)-(2)/(3)(4)(pi)/(2)+(2)/(3)

The area of the region described by A={(x,y):x^(2)+y^(2)<=1 and y^(2)<=1-x} is (A) (pi)/(2)+(4)/(3)(B)(pi)/(2)-(4)/(3)(C)(pi)/(2)-(2)/(3)(D)(pi)/(2)+(2)/(3)

Statement I y = tan^(-1) ( tan x) " and " y = cos^(-1) ( cos x) " does not have nay solution , if " x in (pi/2, (3pi)/2) Statement II y = tan^(-1)( tan x) = x - pi, x in (pi/2, (3pi)/2) " and " y = cos^(-1) ( cos x) = {{:(2pi - x", " x in [pi, (3pi)/2]),(" x, " x in [pi/2,pi]):}

Statement I y = tan^(-1) ( tan x) " and " y = cos^(-1) ( cos x) " does not have nay solution , if " x in (pi/2, (3pi)/2) Statement II y = tan^(-1)( tan x) = x - pi, x in (pi/2, (3pi)/2) " and " y = cos^(-1) ( cos x) = {{:(2pi - x", " x in [pi, (3pi)/2]),(" x, " x in [pi/2,pi]):}

The angle of intersection of the curves y=x^(2), 6y=7-x^(3) at (1, 1), is: a) pi/4 b) pi/3 c) pi/2 d) pi

Find the derivative of y=4x^3-3x^2+2x-pi

If sin ^ (- 1) x + tan ^ (- 1) x = y (-1

If (dy)/(dx) + (4)/(cos^2 x) y = (1)/(cos^2 x) , x in ((-pi)/(3) , pi/3) " and " y (pi/6) = 4/3 " then " y (- pi/6) equals ,

If sinx+cosx=sqrt(y+1/y) for x in [0,pi] , then (a) x=pi/4 (b) y=0 (c) y=1 (d) x=(3pi)/4