" If "cos A*cos2A*cos4A,cos2^(n-1)A=k sin2^(n)A," then "k" is "

cos A cos 2A cos4 A…… cos2^(n-1) A equals

cos A cos 2A cos 4A .......cos^(2^(n-1))A=

Prove that cos A cos 2A cos 2^(2) A cos 2^(3)A....cos 2^(n-1) A=(sin 2^(n) A)/(2^(n) sin A)

Prove that: cos A cos 2A cos 2^(2)A cos 2^(3)A….....cos 2^(n-1)A=("sin" 2^(n)A)/(2^(n)"sin"A) .

cos x*cos2x*cos4x......cos(2^(n-1)x)=(sin2^(n)x)/(2^(n)sin x)AA n in N

The value of cosA cos2A cos2^2A......cos(2^(n-1)A), where A in R may be . (A) 1 (B) -1 (C) 2 (D) sin2^n A/(2^n sinA)

The value of cosA cos2A cos2^2A......cos(2^(n-1)A) , where A in R may be . (A) 1 (B) -1 (C) 2 (D) sin2^n A/(2^n sinA)

Prove that : cos A cos 2A cos 2^2 A cos 2^3 A........ cos 2^(n-1) A= (sin 2^n A)/(2^n sinA) .

Using induction,prove that cos theta cos2 theta cos2^(2)theta...cos2^(n-1)theta=(sin2^(n)theta)/(2^(n)sin theta)