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" (vij) "((sqrt(2))/(5))^(8)-:((sqrt(2))...

" (vij) "((sqrt(2))/(5))^(8)-:((sqrt(2))/(5))^(13)

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(iii) ((sqrt(2))/(5))^(8)-:((sqrt(2))/(5))^(1/3)

Simplify: (i)\ ((sqrt(2))/5)^8\ -:((sqrt(2))/5)^(13)

8. (sqrt(5)-2)^(2)=?-sqrt(80)

(3)/(sqrt(8)-sqrt(2)+sqrt(5))

Simplify the following (sqrt2/5)^8divide(sqrt2/5)^(13)

3sqrt(2^(5))sqrt(4^(9))sqrt(8)=

The following are the steps involved in finding the value of x-y from (sqrt(8)-sqrt(5))/(sqrt(8)+sqrt(5))=x-ysqrt(40) . Arrange them in sequential order. (A) (13-2sqrt(40))/(8-5)=x-ysqrt(40) (B) ((sqrt(8))^(2)+(sqrt(5))^(2)-2(sqrt(8))(sqrt(5)))/((sqrt(8))^(2)-(sqrt(5))^(2))=x-ysqrt(40) (C) x-y=(11)/(3) (D) x=(13)/(3) and y=(2)/(3) (E) ((sqrt(8)-sqrt(5))(sqrt(8)-sqrt(5)))/((sqrt(8)+sqrt(5))(sqrt(8)-sqrt(5)))=x-ysqrt(40)

The sum of the first n terms of the series (1)/(sqrt(2)+sqrt(5))+(1)/(sqrt(5)+sqrt(8))+(1)/(sqrt(8)+sqrt(11))+ .... is

Simplify the following expressions: (11+sqrt(11))(11-sqrt(11))( ii) (5+sqrt(7))(5-sqrt(7))(sqrt(8)-sqrt(2))(sqrt(8)+sqrt(2))