Let `f(x) = asin|x| + be^|x|` is differentiable when

The function f(x)=a sin |x| +be^|x| is differentiable at x=0 when

The function f(x)=asin|x|+be^(|x|) is differentiable at x = 0 when -

Let f(x)=|x-1|+|x+1|. Then f is differentiable in:

Let f : R to R be a function such that f(x+y) = f(x)+f(y),Aax, y in R. If f (x) is differentiable at x = 0, then

Let f(x) be a function differentiable at x=c. Then lim_(x to c) f(x) equals

Let f(x) = x|x| . The set of points, where f (x) is twice differentiable, is ….. .

Let f:R rarr R satisfying f((x+y)/(k))=(f(x)+f(y))/(k)(k!=0,2). Let f(x) be differentiable on R and f'(0)=a then determine f(x)

Let f(x)=x^(3)-9x^(2)+30x+5 be a differentiable function of x , then -