" (ii) "[2times3][[1,2],[-3,0]][[x],[3]]=0

[[2x,3]][[1,2-3,0]][[x3]]=0

If [1, x, 2][[2,3,1],[0,4,2],[0,3,2]][[x],[1],[-1]]=0, then the value of x is

If [1,x,2][[2,3,1],[0,4,2],[0,3,2]][[x],[1],[-1]]=0 , then the value of x is

If [[1,x,1]][[1,2,3],[0,5,1],[0,3,2]][[x],[1],[-2]]=0 , then the value of x is

If [[1,x,1]][[1,3,2],[0,5,1],[0,3,2]][[x],[1],[-2]]=0 , then x is

If A is a 2times2 matrix such that [[2,1],[3,2]] A [[-3,2],[5,-3]]=[[1,0],[0,1]] then the sum of the elements in A is

If [ (2x, 3)] [(1,2),(-3,0)][(x),(8)]=0 , find 'x'

" Let "A" be a "3times3" matrix such that "A[[1,2,3],[0,2,3],[0,1,1]]=[[0,0,1],[1,0,0],[0,1,0]]" .Then "A^(-1)" is "