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" (i) "(sqrt(5)-1)/(sqrt(5)+1)+(sqrt(5)+...

" (i) "(sqrt(5)-1)/(sqrt(5)+1)+(sqrt(5)+1)/(sqrt(5)-1)=a+b sqrt(5)

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(sqrt(5)-1)/(sqrt(5)+1)+(sqrt(5)+1)/(sqrt(5)-1) =a+b sqrt(5) Then find the value of a and b

Simplify each of the following : (i)(sqrt(2)+1)/(sqrt(2)-1)+(sqrt(2)-1)/(sqrt(2)+1)" "(ii)(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))+(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3))" "(iii)(2)/(sqrt(5)+sqrt(3))+(1)/(sqrt(3)+sqrt(2))-(3)/(sqrt(5)+sqrt(2))" "(iv)(sqrt(7)+sqrt(5))/(sqrt(7)-sqrt(5))-(sqrt(7)-sqrt(5))/(sqrt(7)+sqrt(5))

Simplify each of the following : (i)(sqrt(2)+1)/(sqrt(2)-1)+(sqrt(2)-1)/(sqrt(2)+1)" "(ii)(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))+(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3))" "(iii)(2)/(sqrt(5)+sqrt(3))+(1)/(sqrt(3)+sqrt(2))-(3)/(sqrt(5)+sqrt(2))" "(iv)(sqrt(7)+sqrt(5))/(sqrt(7)-sqrt(5))-(sqrt(7)-sqrt(5))/(sqrt(7)+sqrt(5))

12.Rationalise and find the value of' "a'" and "'b'" ; (i) "(sqrt(3)-1)/(sqrt(3)+1)=a+b sqrt(3), (ii) (sqrt(5)-2)/(sqrt(5)+2)=a+b sqrt(5)

The value of (1)/(2)((sqrt(5)+1)/(1+sqrt(5)+sqrt(a))+(sqrt(5)-1)/(1-sqrt(5)+sqrt(a)))(sqrt(a)-(4)/(sqrt(a))+2)sqrt(0.002) is :

If x=(sqrt(5)+1)/(sqrt(5)-1) and y=(sqrt(5)-1)/(sqrt(5)+1) find the value of x^(2)+y^(2)

(1+sqrt(2))/(sqrt(5)+sqrt(3))+(1-sqrt(2))/(sqrt(5)-sqrt(3))