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At 25^(@)C the heat of formation of H(2)...

At `25^(@)C` the heat of formation of `H_(2)O_((l))` is `-285.9" kJ mole"^(-1)` and that for `H_(2)O_((g))` is `-242.8" kJ mole"^(-1)`. The heat of vaporization of water at the same temperature is

A

`43.1" kJ mole"^(-1)`

B

`242.8" kJ mole"^(-1)`

C

`-43.1" kJ mole"^(-1)`

D

`-242.8" kJ mole"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaH=H_(H_(2)O_((g)))-H_(H_(2)O_((l)))`
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Knowledge Check

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