`AB,A_(2)` and `B_(2)` are diatomic molecules. If the bond enthalpies of `A_(2), AB` and `B_(2)` are in the ratio `1:1:0.5` and the enthalpy of formation of `AB` from `A_(2)` and `B_(2)` is `-100kJ mol^(-1)` , what is the bond enthalpy of `A_(2)` ?

Options

A. `200 kJ mol^(-1)`
B. `100 kJ mol^(-1)`
C. `300 kJ mol^(-1)`
D. `400 kJ mol^(-1)`

Answer

D

Explanation

`DeltaH=H_(R)-H_(P)`