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Given C+2S rarr CS(2), DeltaHf^(@)=+11...

Given
`C+2S rarr CS_(2), DeltaHf^(@)=+117.0 kJ mol^(-1)`
`C+O_(2) rarr CO_(2), DeltaHf^(@)=-393.0 kJ mol^(-1)`
`S+O_(2) rarr SO_(2), DeltaHf^(@)=-297.0 kJ mol^(-1)`
The heat of combustion of
`CS_(2)+3O_(2) rarr CO_(2)+2SO_(2)` is

A

`-807 kJ mol^(-1)`

B

`-1104 kJ mol^(-1)`

C

`+1104 kJ mol^(-1)`

D

`+807 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH=H_(P)-H_(R)`
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