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If Delta H("vap") of pure water at 100^(...

If `Delta H_("vap")` of pure water at `100^(@)C` is `40.627 kJ mol^(-1)`. The value of `Delta S_("vap")` is

A

`10.8 91 kJ mol^(-1)`

B

`108.91 Jk^(-1) mol^(-1)`

C

`606.27 JK^(-1) mol^(-1)`

D

`808.27 JK^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaS=(DeltaH)/(T)`
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