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Zn((s))+Cu((aq))^(+2) rarr Cu((s))+Zn((a...

`Zn_((s))+Cu_((aq))^(+2) rarr Cu_((s))+Zn_((aq))^(+2)`
given that `Delta_(f)G^(@)` for `Cu_((aq))^(+2)` and `Zn_((aq))^(+2)` as `65 kJ mol^(-1)` and `-147.2 kJ mol^(-1)` respectively. Then the standard Gibb's energy change for the above reaction is

A

266.2 kJ

B

111.2 kJ

C

`-212.2 kJ`

D

`-122.2 kJ`

Text Solution

Verified by Experts

The correct Answer is:
C

`DeltaG=G_(P)-G_(R)`
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For the Daniel Cell involving the cell reaction Zn_((s))+Cu_((aq))^(+2)hArrZn_((aq))^(+2)+Cu_((s)) the standard free energies of formation of Zn_((s)),Cu_((s)),Cu_((aq))^(+2) and Zn_((aq))^(+2) are 0, 0, 64.4 KJ/Mole and -154.0 KJ/Mole, respectively. Calculate the standard EMF of the cell

Calculate the Gibbs energy change for the reaction given below: Zn_((s))+Cu_((s))^(2+)toCu_((s))+Zn_((aq.))^(2+) Given that standard Gibbs energy ( G^@ ) for Zn_((aq.))^(2+),Cu_((aq.))^(2+) are -147.2 kJ mol^(-1) and 65.0 kJ mol^(-1) respectively.

Calculate DeltaG^(0) for the following reaction, Zn_((s))+Cu_((aq))^(2+)rarrZn_((aq))^(2+)+Cu_((s)).DeltaG_(f)^(0) of Cu_((aq))^(2+) is +65kJmol^(-1)andDeltaG_(f)^(0) of Zn_((aq))^(2+) is - 147.2 kJ mol^(-1)

The standard free energy of Cu_((aq))^(+) is 50 kJ mol^(-1) and that of Cu_((aq))^(2+) is 66 kJ. mol^(-1) . Calculate the change in free energy for the reaction, Cu_((aq))^(+)rarrCu_((aq))^(2+)+e^(-) .

Represent the galvanic cell in which the reaction Zn_((s))+ Cu_((aq))^(2+)rightarrowZn_((aq))^(2+)+Cu_(s) take place .

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