A system is provided with 50 Joules of heat and the work done on they system is 10 Joules. What is the change in internal energy of the system in Joules?

Options

A. 60
B. 40
C. 50
D. 10

Explanation

To find the change in internal energy of the system, we can use the first law of thermodynamics, which states:

\[ \Delta U = Q + W \]

where:
- \(\Delta U\) is the change in internal energy,
- \(Q\) is the heat added to the system,
- \(W\) is the work done on the system.

### Step-by-Step Solution:

1. **Identify the given values**:
- Heat added to the system, \(Q = 50 \, \text{J}\)
- Work done on the system, \(W = 10 \, \text{J}\)

2. **Apply the first law of thermodynamics**:
- According to the formula, we substitute the values of \(Q\) and \(W\):
\[ \Delta U = Q + W \]
\[ \Delta U = 50 \, \text{J} + 10 \, \text{J} \]

3. **Calculate the change in internal energy**:
- Perform the addition:
\[ \Delta U = 60 \, \text{J} \]

4. **State the final answer**:
- The change in internal energy of the system is \(60 \, \text{J}\).

### Final Answer:
\[ \Delta U = 60 \, \text{J} \]