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H(2)(g)+I(2) (s) rarr 2HI (g), DeltaH=51...

`H_(2)(g)+I_(2) (s) rarr 2HI (g), DeltaH=51.9` KJ/mole
`H_(2)(g)+I_(2)(g) rarr 2 HI (g), DeltaH=-9.2` kJ/mole.
the heat of reaction of `I_(2)(s) rarr I_(2) (g)`

A

`-61.1 kJ`

B

`+61.1 kJ`

C

`+31.1 kJ`

D

`50.1 kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH=H_(I_(2)(g))-H_(I_(2)(s))`
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