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The bond energy of H(2) is 104.3 k.cal m...

The bond energy of `H_(2)` is `104.3 k.cal mol^(-1)`. It means that

A

104.3 K. cal heat is released during breaking up 'N' bonds in N molecules of `H_(2)`

B

104.3 K. cal heat is needed to break up `6.023 xx10^(23)` molecules into `1.2046xx10^(24)` ayoms of H

C

104.3 K. cal heat is evolved during combination of 2N atoms of H to form N molecules of `H_(2)`

D

Both 2 and 3.

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The correct Answer is:
D
Definition of bond enthalpy
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