Assuming that water vapour is an ideal gas, the internal energy change `(DeltaU)` when 1 mole of water is vaporised at `1 ba r` pressure and` 100^(@)C, (` given`:` molar enthalpy of vaporization of water `41kJ mol^(-1)` at `1 ba r` and `373 K ` and `R=8.3 J mol^(-1)K^(-1))` will be `:`

Options

A. `41 kJ mol^(-1)`
B. `4.1 kJ mol^(-1)`
C. `3.7904 kJ mol^(-1)`
D. `37.904 kJ mol^(-1)`

Answer

D

Explanation

`DeltaH=DeltaU+Delta nRT`