1.3+3.5+5.7+...+(2m-1)(2 pi+1)=m(4-2)^(2)+10

The A.M.of the observations 1.3.5,3.5.7,5.7.9,......,(2n-1)(2n+1)(2n+3) is (AA n in N)

The A.M of the observations 1.3.5,3.5.7,5.7.9,...,(2n-1)(2n+1)(2n+3) is

(2m+5)/(3)=3m-10

(m-5)/(2)-(m-3)/(5)=(1)/(2)

(2m^(2)-3m+10)-:(m-5)

Fiind m, if the lines (1-x)/(3)= ( 7y-14)/(2m ) = (z-3) /(2) and ( 7-7x)/(3m) = (y-5)/(1) = (6-z)/(5) are at right angles.

Ifm-(1)/(m)=5, find (1)m^(2)+(1)/(m^(2))(pi i)m^(2)-(1)/(m^(2))

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

If m is a real number such that m^(2)+1=3m the value of (2m^(5)-5m^(4)+2m^(3)-8m^(2))/(1+m^(2))