The value of enthalpy change `(DeltaH)` for the reaction
`C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l)`
at `27^(@)C` is `-1366.5 kJ mol^(-1)`.
The value of internal energy change for the above reactio at this temperature will be

Options

A. `-1371.5 kJ`
B. `-1369.0 kJ`
C. `-1364.0 kJ`
D. `-1361.6 kJ`

Answer

C

Explanation

`Delta H=Delta U+Delta n_(g) RT` where,
`Deltan_(g) = ("moles of gaseous products") - ("moles of gaseous reactants")`
for the given reaction,
`Delta n_(g)=2-3=-1`
`-1366.5=DeltaU-1xx8.314xx10^(-3) xx300`
`:. DeltaU=-1364.0 kJ mol^(-1)`