The enthalpies of combustion of carbon and carbon monoxide are `-393.5` and `-283` kJ `mol^(-1)` respectively. The enthaly of formation of carbon monoxide per mole is :

Options

A. `676.5`
B. `-676.5`
C. `110.5`
D. `110.5`

Answer

C

Explanation

`CO(g)+1/2 O_(2) (g) rarr CO_(2) (g), DeltaH=-283.5 kJ mol^(-1)` ...(ii)
Eq (i) - Eq (ii) gives
`C(s)+1/2O_(2) (g) rarr CO(g), Delta_(f)H=-110.5 kJ mol^(-1)`