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One mole of an ideal diatomic gas absorb...

One mole of an ideal diatomic gas absorbs 1831.4 J of heat and does 1000 J of work at `27^(@)C`. What is the change in temperature observed ?

A

`25^(@)C`

B

`40^(@)C`

C

`37^(@)C`

D

`67^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B

`q_(V) = C_(V)Delta T`
`Delta T = (q_(V))/(C_(V)) = (831.4 J)/((5)/(2)R)`
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