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Calculate the change in enthalpy for the...

Calculate the change in enthalpy for the following process at 1 atm
`H_(2)O(1, 50^(@)C) rarr H_(2)O (g, 150^(@)C)` given that `Delta H_(v)` at `100^(@)C` is `40.7 kJ mol^(-1)`
`C_(p)(H_(2)O, l) = 75.0 J mol^(-1)K^(-1)`
`C_(p)(H_(2)O, g) = 33.3 J mol^(-1)K^(-1)`

A

64.8 KJ

B

52.4 KJ

C

48.6 KJ

D

46.1 KJ

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)0_((l))(50^(@)C) rarr H_(2)O_((l))(100^(@)C) rarr H_(2)O_((g))(150^(@)C)`
Total heat absorbed
`= Delta_("temp. rise") H_((50 rarr 100))+Delta_(Vap)H+Delta_("temp.rise")H_((100 rarr 150))`
`= C_(P)Delta T + Delta_(Vap)H+C_(P)Delta T`
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