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H(2)O((g)) rarr H((g))+OH((g))Delta H = ...

`H_(2)O_((g)) rarr H_((g))+OH_((g))Delta H = x_(1)`
`OH_((g)) rarr H_((g))+O_((g))Delta H = x_(2)`
Based on the these value, BE of O-H bond is

A

`(x_(1)+x_(2))/(2)`

B

`x_(1)+x_(2)`

C

`(x_(1)-x_(2))/(2)`

D

`2(x_(1)+x_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H = H_(r) - H_(P)`
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